You make a capacitor by cutting the 16.0-cm-diameter bottoms out of two aluminum pie plates, separating them by 3.25 mm, and connecting them across a 6.00 V battery. What is the capacitance of your capacitor?

The capacitance of your capacitor is 5.476 x 10⁻⁵ μF

Explanation:

Given;

diameter of the aluminum pie plates = 16 cm = 0.16 m

separation distance, d = 3.25 mm = 0.00325 m

voltage across the parallel plates = 6 V

where;

C is the capacitance of your capacitor

ε is the permittivity of free space = 8.85 x 10⁻¹²  (F/m)

d is separation distance

A is the area of the plate = ¹/₄ (πd²) = 0.25 (π x 0.16²) = 0.02011 m²

Therefore, the capacitance of your capacitor is 5.476 x 10⁻⁵ μF

the answer is a. at the equator

a and c

c is 100% but i am confused in a