Batman is fighting superman. He throws his 5 kg fist at superman with a speed of 9 m/s. Superman stops the punch with a force of 45,000 N. How much time did it take for batman's hand to stop moving?

1 × 10^-3 s.

Explanation:

Given:

Mass = 5 kg

V = 9 m/s

Force = 45000 N

Using Newton's law,

Force = mass × acceleration

= (mass × velocity)/time

45000 = (5 × 9)/time

Time = 1 × 10^-3 s.

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.