When Woods hits a 0.04593 kg golf ball, the golf ball is usually traveling around 281 kilometers per hour. What average force does he exert on a golf ball if the club head and golf ball are in contact for 0.030 seconds?

128.9 N

Explanation:

The force exerted on the golf ball is equal to the rate of change of momentum of the ball, so we can write:

where

F is the force

is the change in momentum

is the time interval

The change in momentum can be written as

where

m = 0.04593 kg is the mass of the ball

u = 0 is the initial velocity of the ball

is the final velocity of the ball

Substituting into the original equation, we find the force exerted on the golf ball:

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.

lol

explanation: