If the gas inside the flask in the above exercise is cooled so that its pressure is reduced to a value of 715.7 torr, what will be the height of the mercury in the open ended arm? (Hint: The sum of the heights in both arms must remain constant regardless of the change in pressure.) (a) 49.0 mm, (b) 95.6 mm, (c) 144.6 mm, (d) 120.1 mm.

(a) 49.0 mm

Explanation:

#First we need to calculate the height of the mercury arm:

Reduced pressure is 715.7torr, Initial Pressure is 797.3torr, Required pressure is:

The difference in the two arms will give the pressure difference between the gas placed in the flask attached to an open-end mercury manometer.

Hence the height of the mercury in the arm is 49.00mm

does anyone know or what?

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