In a pickup game of dorm shuffleboard, students crazed by final exams use a broom to propel a calculus book along the dorm hallway. If the 3.5 kg book is pushed from rest through a distance of 0.90 m by the horizontal 25 N force from the broom and then has a speed of 1.60 m/s, what is the coefficient of kinetic friction between the book and floor?

μ = 0.145

Explanation:

For this this problem let's start by using the kinematic relations to find the acceleration of the body

          v² = v₀² + 2 a x

As part of rest v₀ = 0

         a = v² / 2x

         a = 1.60²/2 0.90

         a = 1.42 m / s²

Now we can use Newton's second law

         fr = m a

         N- W = 0

The equation for friction force is

         fr = μ N

         fr = μ m g

We replace

        μ m g = m a

        μ = a / g

        μ = 1.42 /9.80

        μ = 0.145

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explanation: