A 75-g projectile traveling at 600 m /s strikes and becomes embedded in the 40-kg block, which is ini-tially stationary. Compute the energy lost during the impact. Express your answer as an absolute value ΔE| and as a percentage n of the original system energy E.

Explanation:

The given data is as follows.

          Mass, m = 75 g

         Velocity, v = 600 m/s

As no external force is acting on the system in the horizontal line of motion. So, the equation will be as follows.

where,   = mass of the projectile

            = mass of block

              v = velocity after the impact

Now, putting the given values into the above formula as follows.

                                  =

                              v = 0.898 m/s

Now, equation for energy is as follows.

               E =

                  =

                  = 13500 J

Now, energy after the impact will be as follows.

             E' =

                 = 20.19 J

Therefore, energy lost will be calculated as follows.

            = E  E'

                       = (13500 - 20) J

                       = 13480 J

And,   n =

             =

             = 99.85

             = 99.9%

Thus, we can conclude that percentage n of the original system energy E is 99.9%.

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.