At 25°C and 754 torr, 2.50 moles of Ne occupies a volume of 60.6 L. At constant temperature and pressure, how many moles of Ne must be removed to reduce the volume to 45.0 L?

number of moles removed = 0.6436 moles

Explanation:

given data

volume v1 = 60.6 L

volume v2 = 45.0 L

moles of Ne n1 = 2.50 moles

temperature =  25°C

solution

we will use here gas law  that is express as

PV = nRT   .........................1

so here we get here  number of moles

so equation will be as

P1 × V1 = n1 × R × T1

and

P2 × V2 = n2 × R × T2

so from above two equation we can say at pressure and temperature constant so

   ...............2

put here value we get

n2 = 1.856 moles

so 1.856 moles occupied when volume is 45 L

so here number of moles removed will be

number of moles removed = initial moles - final moles    ...............3

put here value

number of moles removed = 2.50 - 1.856

number of moles removed = 0.6436 moles

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