A locomotive is accelerating at 3.08 m/s2. It passes through a 20.8-m-wide crossing in a time of 2.93 s. After the locomotive leaves the crossing, how much time is required until its speed reaches 29.4 m/s?

Required time t=5.8s

Explanation:

Given data

Acceleration a=3.08 m/s²

Speed v=29.4 m/s

Required

How much time t is required

Solution

As the train passes through the crossing its motion is described by:

Substitute the given values

So

So time required can be calculated by:

Required time t=5.8s

0.19 m/s and 0.45 m/s

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.