A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and the outer is positively charged; the magnitude of the charge on each is 11.5 pC. The inner cylinder has a radius of 0.550 mm, the outer one has a radius of 4.00 mm, and the length of each cylinder is 15.0 cm.

(1) What is the capacitance? Use 8.854×10−12 F/m for the permittivity of free space.
(2) What applied potential difference is necessary to produce these charges on the cylinders?

Explanation:

a.

Given the permittivity constant to be ,The capacitance of a of length, is given by the equation:

where is the radius of the outer cylinder and the radius of the inner cylinder.

The values are given as:

Substitute in our capacitance equation:

Hence the capacitance is

b. The charge on the capacitance is related to the potential difference across it. The potential difference is expressed using the equation:

,

From a above, we already have our capacitance value,

We substitute in the pd equation:

Hence, the applied potential difference is 2.7344V

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

the maxium height is 34m/s