How do you do this question?

Explanation:

The total surface area is:

A = 2πr² + 2πrL

A = 2π (3.3 cm)² + 2π (3.3 cm) (12 cm)

A = 317.24 cm²

If ρ is the mass per area density in g/cm², then:

m = ρA

50 g = ρ (317.24 cm²)

ρ = 0.158 g/cm²

(a) The mass of the lid is:

m = ρA = ρ πr²

m = (0.158 g/cm²) (π (3.3 cm)²)

m = 5.39 g

(b) The mass of the shell is:

M = ρA = ρ 2πrL

M = (0.158 g/cm²) (2π (3.3 cm) (12 cm))

M = 39.22 g

(c) The moment of inertia of the lid/bottom is I = 1/2 mr².

The moment of inertia of the shell is I = Mr².

The total moment of inertia is:

I = 1/2 mr² + Mr² + 1/2 mr²

I = (m + M) r²

I = (5.39 g + 39.22 g) (3.3 cm)²

I = 485.78 g cm²

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

v=ir = 3x15 =45 v