A spaceship is in an elliptical orbit in the equatorial plane of an exoplanet. The navigator makes the following observations:

The planet's equatorial angular diameter at periapsis is 16.3060482°
The planet's equatorial angular diameter at apoapsis is 12.0634564°
The planet's polar angular diameter at periapsis is 16.2567986°
The planet's polar angular diameter at apoapsis is 12.0271323°
The sidereal period of the spaceship's orbit is 108,000 seconds.
The spaceship's altitude above surface of the exoplanet at periapsis is 52,568,218 meters.

Find the exoplanet's mass.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j