A "biconvex" lens is one in which both surfaces of the lens bulge outwards. Suppose you had a biconvex lens with radii of curvature with magnitudes of |R1|=10cm and |R2|=15cm. The lens is made of glass with index of refraction nglass=1.5. We will employ the convention that R1 refers to the radius of curvature of the surface through which light will enter the lens, and R2 refers to the radius of curvature of the surface from which light will exit the lens.

C) What is the focal length of the lens if it is immersed in water (nwater = 1.3)
f= cm

What is the focal length f of this lens in air (index of refraction for air is nair=1)?

f=150cm in water and f=60cm in air.

Explanation: Focal length is a measurement of how strong light is converged or diverged by a system. To find the variable, it can be used the formula:

= (nglass - ni)( - ).

nglass is the index of refraction of the glass;

ni is the index of refraction of the medium you want, water in this case;

R1 is the curvature through which light enters the lens;

R2 is the curvature of the surface which it exits the lens;

Substituting and calculating for water (nwater = 1.3):

= (1.5 - 1.3)( - )

= 0.2()

f = = 150

For air (nair = 1):

= (1.5 - 1)( - )

f = = 60

In water, the focal length of the lens is f = 150cm.

In air, f = 60cm.

nah.   i'm just sleepy.

the force on the thing and the distance the force moves the thing