Physics, 07.03.2020 05:33, alyssamonae
A 0.40-kg object is traveling to the right (in the positive direction) with a speed of 4.0 m/s. After a 0.20 s collision, the object is traveling to the left at 2.0 m/s. What is the magnitude of the impulse (in N-s) acting on the object
Answers: 2
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![\Sigma F \cdot \Delta t = (0.40 kg) \cdot [- 2 \frac{m}{s} - 4 \frac{m}{s} ]\\\Sigma F \cdot \Delta t = - 2.4 N \cdot s](/tpl/images/0537/9773/d543b.png)
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A 0.40-kg object is traveling to the right (in the positive direction) with a speed of 4.0 m/s. Afte...
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