If a constant friction force of magnitude 11 Newtons is exerted on the block by the surface, find the magnitude of the acceleration of the block. Answer in units of m/s 2

acceleration a = 3.67 m/s^2

Completed Question:

A block of mass 3 kg, which has an initialspeed of 6 m/s at timet= 0, slides on ahorizontal surface. If a constant friction force of magnitude 11 Newtons is exerted on the block by the surface, find the magnitude of the acceleration of the block. Answer in units of m/s 2

Explanation:

Force = mass × acceleration

F = ma 1

Given that;

Force F = 11 N

mass m = 3 kg

Acceleration a can be derived from equation 1

Making a the subject of formula;

a = F/m

Substituting the given values;

a = 11N/3kg

a = 3.66666... m/s^2

acceleration a = 3.67 m/s^2

b.a device that inputs heat into a cool object

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s