A weight watcher who normally weighs 400 N stands on top of a very tall ladder so she is one Earth radius above the Earth's surface. How much would she weigh there

Explanation:

The weight of the body on the surface of earth can be found by the relation

W₁ =                        I

Here G is gravitational constant and M is the mass of earth .

m is the mass of the body

and R is the radius of earth  or the distance of body from the center of the earth .

Now  she moves to height equal to R . Thus the distance from center of earth becomes 2 R .

Thus Weight now is W₂ =                   II

Dividing II by I , we have

=

But W₁ = 400 N

Thus W₂ = = 100 N

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.