Physics, 06.03.2020 23:50, Needalittlehelp
A puck of mass m moving at speed v on a horizontal, frictionless surface is stopped in a distance d because a hockey stick exerts on an opposing force of magnitude F on it.
F = (mv^2) / 2d
If the stopping distance d increases 40%, by what percent does the average force needed to stop the puck change, assuming that m and v are unchanged?
(Fnew - F) / F = ? %
Answers: 3
![\% Change = [\frac{1}{2.8} -\frac{1}{1}]*100 = -64.29\%](/tpl/images/0536/5820/d9529.png)
![\% Change = \frac{\frac{mv^2}{2d}}{\frac{mv^2}{2d}} [\frac{1}{2.8} -\frac{1}{1}]*100](/tpl/images/0536/5820/7aee4.png)
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A puck of mass m moving at speed v on a horizontal, frictionless surface is stopped in a distance d...
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