A 5.0 mm diameter proton beam carries a total current of 1.5mA. The current density in the proton beam, which increases with distance from the center, is given by J = Jedge(r/R), where R is the radius of the beam and Jedge is the current density at the edge. I calculated that 9.375 x 10^15 protons are delivered by the proton beam each second, but I do not know where to start in calculating the value of Jedge.
Answers: 3
Physics, 21.06.2019 13:30, janetshirinyan
Use the data provided to calculate the gravitational potential energy of each cylinder mass. round your answers to the nearest tenth. 3 kg: kj 6 kg: kj 9 kg: kj
Answers: 3
Physics, 22.06.2019 03:00, coryintheswamp
What are the applications of electromagnetic waves
Answers: 1
A 5.0 mm diameter proton beam carries a total current of 1.5mA. The current density in the proton be...
Social Studies, 19.10.2019 06:00
Mathematics, 19.10.2019 06:00
Mathematics, 19.10.2019 06:00
Mathematics, 19.10.2019 06:00
Chemistry, 19.10.2019 06:00
World Languages, 19.10.2019 06:00