The acceleration of gravity on Mars is about 3.7 meters per second squared. Suppose a rock falls from a tall cliff on Mars. Write the equation that indicates how fast the rock will be falling after 8 seconds?

The answer to your question is  Equation  vf = gt;  vf = 29.6 m/s

Explanation:

Data

gravity = 3.7 m/s²

vf = ?

time = t = 8 s

Formula

       vf = vo + gt

Initial speed = 0 m/s

To solve this problem we can use the equations of free fall and just substitute the data.

- Substitution

      vf = 0 + (3.7)(8)

- Simplification

      vf = 29.6 m/s

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

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