Projectile is fired in such away that its horizantal range is equa to three times its maximum height . what is the angle of projectile

Using the following formulas:

Range = [ Vo^2 * sin 2*theta ]/g

Height = [ Vo^2 * sin theta^2 ]/g

Since the relation between Range and height is given: ( R = 3H ), the 2 equations can be equated in terms of Vo^2 so that the only remaining unknown variable left will be the angle. This is done as shown:

( g*Range )/(sin 2*theta) = Vo^2
( g*Height )/(sin theta^2) = Vo^2


( g*Range )/(sin 2*theta) = ( g*Height )/(sin theta^2)

Applying Range = 3*Height:
( g*3*Height )/(sin 2*theta) = ( g*Height )/(sin theta^2)

substituting given values while Height cancels out:

( 9.8*3 )/(sin 2*theta) = ( 9.8 )/(sin theta^2)
Angle theta = 33.67 degrees
 

Texture and composition are different because they are not the same aspect. texture has to do with feel and so on, where as composition is the chemical makeup which you cant touch like you can texture.