A 55-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.30, and the coefficient of kinetic friction is 0.20. What horizontal force must be applied to the box to cause it to start sliding along the surface

Horizontal force is defined as the forces that equal and opposite in the direction. The horizontal resultant force is always zero.

Given that:

Mass of box = 55 Kg

Coeeficient of Static friction = 0.30

Coefficient of kinetic friction = 0.20

The box if have to slide, then it would have to overcome the static force, such that:

F - Fs = 0

F = Fs

The force will be:

F =

F =

F = 161.7 Newton

Thus, the force required to slide the box is 161.7 Newton.

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The horizontal force that must be applied to the box to cause it to start sliding along the surface is 162N

Explanation:

To start sliding the box on the surface it must overcome its static frictional force  under equilibrium condition

The net force on the box is

F - fs = 0

F = fs = us N = us mg

Force = ( 0.3) x ( 55 kg) x ( 9.8 m/s^2) = 161.7 approximately 162 N

answer: b.

explanation: