A 1-kg discus is thrown with a velocity of 19 m/s at an angle of 35 degrees from the vertical direction. calculate the vertical and horizontal velocity components.

15.56m/s and 10.90m/s respectively

The vertical and horizontal components of a given vector, say A, are given by

= A sin θ                  ----------------(i)

= A cos θ                 ----------------(ii)

Where;

is the vertical component of the vector A

is the horizontal component of the vector A

A is the magnitude of the vector A

θ is the angle the vector makes with the positive x-axis (horizontal direction).

Now, from the question;

The vector is the velocity of the 1-kg discus. Lets call it vector V

The magnitude of the velocity vector V = V = 19m/s

The angle that the vector makes with the positive x-axis = θ

To calculate θ;

Notice that the velocity vector makes an angle of 35° from the vertical direction rather than the horizontal direction.

Therefore, to get the horizontal direction of the velocity vector, we subtract 35° from 90° as follows;

θ = 90° - 35° = 55°

Now, the vertical and horizontal components of the velocity vector, V, are given by

= V sin θ              --------------------(iii)

= V cos θ             ------------------------(iv)

Substitute all the necessary values into equations(iii) and (iv) as follows;

= 19 sin 55° = 19m/s x 0.8192 = 15.56m/s

= 19 cos 55° = 19m/s x 0.5736 = 10.90m/s

Therefore, the vertical and horizontal velocity components are respectively 15.56m/s and 10.90m/s.

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.

firearm identification is the process of analyzing the bullets and cartridge cases left at a crime scene to determine if they came from a particular firearm. marks on the bullets and cartridges may be common to every firearm of that type. these are called class characteristics.