A chlorine and bromine atom are adsorbed on a small patch of surface (see sketch at right). This patch is known to contain possible adsorption sites. The and bromine atoms have enough energy to move from site to site, so they could be on any two of them. Suppose the atom desorbs from the surface and drifts away. Calculate the change in entropy. Round your answer to significant digits, and be sure it has the correct unit symbol.

ΔS = - 3.74 × 10⁻²³ J/K = - 3.7 × 10⁻²³ to 2 s.f

Explanation:

The change in entropy for a system with changing allowable Microsystems is given as

ΔS = K In (W/W₀)

K = Boltzmann's constant = 1.381 × 10⁻²³ J/K

W₀ = initial number of microstates

To calculate this, how many ways can 2 atoms occupy 16 available microstates with order important?

That is, ¹⁶P₂ = 16!/(16 - 2)! = 16 × 15 = 240 microstates.

W = the number of microstates for Chlorine atom when Bromine atom desorps = 16 microstates.

ΔS = K In (W/W₀)

ΔS = (1.381 × 10⁻²³) In (16/240)

ΔS = (1.381 × 10⁻²³) × 2.7081

ΔS = - 3.74 × 10⁻²³ J/K

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

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