A stretched spring has a total length of 20 cm and a spring constant of 200 N/m. It is storing 0.25 J in its elastic potential energy store. Determine the unstretched length of the spring. (Please answer ASAP thank you!)

The unstretched length of the spring is 0.15 m

Explanation:

Given-

Length of the stretched spring, = 20 cm = 0.2 m

K = 200 N/m

U = 0.25 J

unstretched length of the spring, x₀ = ?

We know,

U = (Δx)²

Δx = - x₀

Δx = 0.2 - x₀

0.25 = 100 (0.2 - x₀)²

0.0025 = (0.2 - x₀)²

0.05 = 0.2 - x₀

x₀ = 0.15 m

Therefore, the unstretched length of the spring is 0.15 m

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