A deuteron, with the same charge but twice the mass of a proton, moves with a speed of 6.00 × 105 m/s perpendicular to a uniform magnetic field of 0.0525 T. Which of the paths described below would it follow? (qp = 1.60 × 10−19 C and md = 3.34 × 10−27 kg)

Explanation:

The given data is as follows.

     v =

     B = 0.0525 T,    q =

     m =

It is known that relation between mass and magnetic field is as follows.

or,       r =

So, putting the given values into the above formula and we will calculate the radius as follows.

             r =

               =

               =

               = 0.238 m

Thus, we can conclude that radius of the circular path is 0.238 m.

The radius is

Explanation:

Given that,

Speed

Magnetic field = 0.0525 T

We need to calculate the radius

Using relation of centripetal force and magnetic force

Put the value into the formula

Hence, The radius is

the answer would be c. motion and direction

i hope this : )