(a) All our household circuits are wired in parallel. Below is an example of a simple household circuit with 3 identical bulbs with resistance of 100 Ω each. Assume that this is the standard household 120 V circuit. What is the current running through each bulb? bulb 1 bulb 2 bulb 3

Same current flows through bulb 1, bulb and bulb 3 = 1.2 A

Explanation:

Note: Since the bulbs are connected in parallel, They will have a common voltage

From ohm's law,

V = IR Equation 1

Where V = Voltage, I = current, R = Resistance.

make I the subject of the equation

I = V/R Equation 2

For Bulb 1

Given: V = 120 V, R = 100 Ω

substitute into equation 2

I = 120/100

I = 1.2 A.

For Bulb 2

Given: V = 120 V, R = 100 Ω

Substitute into equation 2

I = 120/100

I = 1.2 A.

For Bulb 3

Similarly,

I = 120/100

I = 1.2 A.

Hence the same current flows through bulb 1 bulb and bulb 3 = 1.2 A

Explanation:

Below is an attachment containing the solution.

6 cos 34, 6 sin 34 trig