How much work did the movers do (horizontally) pushing a 46.0-kg crate 10.4 m across a rough floor without acceleration, if the effective coefficient of friction was 0.60? Express your answer using two significant figures.

The total work done by the mover is 2.81 kJ.

Explanation:

Given the 46 kg crate is displaced by 10.4 meters.

And the acceleration is zero. Also,

let is applied force, is the net force, is the mass and

and

As the acceleration is zero, the net force will also be zero.

.

Now, we know the work done is force times displacement.

So,

So, the total work done by the mover to displace 46 kg crate by 10.4 meters 2.81 kJ.