MATHPHYS HELP
The force required to stretch a spring varies
directly with the amount the spring is
stretched. A spring stretches by 98 m when
a 78 N weight is hung from it and the weight
is at rest (at equilibrium). The 78 N weight
is replaced by an unknown weight W so that
the spring is stetched to a new equilibrium
position, 67 m below the position if no weight
were attached. The weight W is then dis-
placed from equilibrium and released so that
it oscillates.

16.4287

Explanation:

The force and displacement are related by Hooke's law:

F = kΔx

The period of oscillation of a spring/mass system is:

T = 2π√(m/k)

First, find the value of k:

F = kΔx

78 N = k (98 m)

k = 0.796 N/m

Next, find the mass of the unknown weight.

F = kΔx

m (9.8 m/s²) = (0.796 N/m) (67 m)

m = 5.44 kg

Finally, find the period.

T = 2π√(m/k)

T = 2π√(5.44 kg / 0.796 N/m)

T = 16.4287 s

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation:

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.