The force per meter between the two wires on a jumper cable being used to start a stalled car is 0.225 N/m. What is the current (A) in the wires, given that they are separated by 2.00 cm

150 A

Explanation:

The magnitude of the force per unit length between two current-carrying wires is given by

where

is the vacuum permeability

are the currents in the two wires

r is the distance between the wires

And the force is:

In this problem, we have:

is the force per unit length

is the distance between the wires

The two wires carry the same current, so

Therefore we can re-arrange the equation to find the current:

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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b.

explanation: