A sound wave has a frequency of 628 Hz in air
and a wavelength of 0.49 m.
What is the temperature of the air? Assume the velocity of sound at 0^◦C is 325 m/s.
Answer in units of ◦C.

Answer is 257°C

Explanation:

Given

frequency = 628 Hz

wavelength = 0.49 m

speed of sound at 0°C = 325 m/s

Find

1.speed of sound at t °C=?

2.temperature = ?

Formula

speed of sound at t °C = speed of sound at 0°C   [1+t/273]

Solution

1. speed of sound at t °C = f*∧

                                        = 628*0.49

                                        =307.7m/s

2.speed of sound at t °C = speed of sound at 0°C   [1+t/273]

                    307.7 m/s    = 325 m/s [1+ t/ 273]

                    307.7/325   = 1+t/273

                    0.94             = 1+t/273

              multiplying 273 on both sides

                     (0.94)(273)  = 1+t/273 (273)

                      258             = 1+ t

                       258 - 1        = t

                             257°C    = t

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

the closer the planet is to the sun, the larger the gravity