If a platform diver has 7350 J of energy when he stands on top of the platform, how
much kinetic energy will the diver have when he hits the water?
A. OJ
B. 3675 J
C. 7350 J

C. 7350 J

Explanation:

The total mechanical energy of an isolated system, given by the sum of its potential energy and its kinetic energy, is constant:

where

PE is the potential energy,  the energy due to the location of the object in the gravitational field

KE is the kinetic energy, the energy due to the motion of the object

In this problem, the diver is initially standing on the platform with a potential energy of

PE = 7350 J

At the beginning, the diver is at rest, so its kinetic energy is zero:

KE = 0

However, as he falls down, its potential energy converts into kinetic energy, since the height decreases but the speed increases.

Eventually, when the diver reaches the water, all its potential energy has converted into kinetic energy, so we will have:

PE = 0

KE = 7350 J

So, the final kinetic energy is 7350 J.

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