A) An electron is moving east in a uniform electric field of 1.48 N/C directed to the west. At point A, the velocity of the electron is
4.55
×
10
5
m/s pointed towards the east.

What is the speed of the electron when it reaches point B which is a distance of 0.370 m east of point A?

B) A proton is moving in the uniform electric field of part (A), at which point A, the velocity of the proton is
1.91
×
10
4
m/s, again points towards the east.

What is the speed of the proton at point B?

A)3074m,3074.37m/s

B)12905.4m,19100.54m/s

Explanation:the formula for electric field =V/d

Where V=velocity of the particle,d=distance covered from the electric field source

A)E=V/d

1.48=4.55×10^5/d

d=4.55×10^5/1.48=3074m

Distance of B from centre of the field=3074+0.370=3074.370m

B)d=V/E=1.91×10^4/1.48

d=12905.4m

At point B

Distance=12905.4+0.370=12905.770

V=Ed=12905.770×1.48=19100.54m/s

i think its c if i'm wrong

no. bullets are macro objects. wave nature is for light waves, extremely tiny particles. if a light particle was the size of your finger, the bullet would be the size of the universe. so basically, that huge difference in size makes the wave nature of matter insignificant.