Physics, 28.02.2020 19:30, RiddleMeThis
A simple pendulum is swinging back and forth through a small angle, its motion repeating every 1.15 is. How much longer should the pendulum be made in order to increase its period by 0.22 s?
Answers: 3
![=\frac{T_{2}^{2}g }{4 \pi^{2} }-\frac{T_{1}^{2}g }{4 \pi^{2} }\\=\frac{g}{4 \pi^{2} }[T_2^{2} -T_1^{2} ]\\ =\frac{9.8}{4 \pi^{2}}[(1.15+0.22)^{2}-(1.15)^{2} ] \\=0.14m](/tpl/images/0528/2082/118ea.png)
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A simple pendulum is swinging back and forth through a small angle, its motion repeating every 1.15...
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