A 200-N sled of slides down a frictionless hillside that rises at 37° above the horizontal. What is the magnitude of the force that the hill exerts on the sled parallel to the surface of the hill?

120 N

Explanation:

Given the angle of inclination of 200 N sled is 37°.

We need to find the magnitude of the force that the hill exerts on the sled parallel to the surface of the hill.

We can see from the diagram, the force that the hill exerts on the sled parallel to the surface of the hill is

As we have given the weight of the sled was 200 N. So,

Now,

So, 120 N is the force that sled exerts parallel to the surface of the heal.

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

hope this ! this is not copied! search it up, it's free of plagiarism!