A 200-ω resistor is rated at 1/4 w. What is the maximum voltage that can safely be connected across it?

7.07volts

Explanation:

Power generated by a load or resistor in an electric circuit is represented as P = IV... (1) where;

P is the power measured in watts (W)

I is the current flowing through the resistor in amperes

V is the maximum voltage passed across the circuit in volts

According to ohms law V = IR; I = V/R... (2)

Substituting equation 2 into 1

P = IV

P = V/R×V

P = V²/R

Given the power rating = 1/4w

Resistor = 200ohms

V² = PR

V² = 200×1/4

V² = 50

V = √50

V = 7.07volts

Therefore the maximum voltage that can safely be connected across it is 7.07Volts.

the electric field is a “force field” around a charged object that illustrates the direction the electric force would push an imaginary