Two blocks are in contact on a frictionless, horizontal tabletop. An external force, F ,is applied to block 1, and the two blocks are moving with a constant acceleration of 2.70 m/s2. Use M1 = 3.03 kg and M2 = 6.40 kg. (a) What is the magnitude, F, of the applied force? (b) What is the contact force between the blocks? (c) What is the net force acting on block 1? {25.5 N, 17.3 N, 8.18 N to the right}

Explanation:

The blocks are moving in the x direction

Given that,

m1=3.03kg

m2=6.40kg

After a force F is applied to the two masses they move with an acceleration of 2.7m/s²

Newton's Second Law:

ΣF = Σ(ma) = m1a1 + m2a2

Therefore

But in this case a1 =a2=2.7m/s², because they are connected by a string and they are accelerating at the same speed.

F=(m1+m2)a

F=(3.03+6.40)2.7

F=9.43 ×2.7

F=25.46N.

b. The contact force be blocks

F2= m2a

F2 is the force between the blocks

F2=6.4×2.7

F2= 17.28N

c. Fnet on block 1

It is the net force pulling the two blocks forward minus the force between the block 1 and 2

F1=F-F2

F=25.46-17.28

F=8.18N

The net force on block 1 is 8.18N

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answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.