A rock hits the ground with a speed of 13 m s−1
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1
and a kinetic energy of 300 J. What is the rock’s mass?

3.55kg

Explanation:

K. E = ½mv²

Where m = mass,  v = velocity

K. E = 300J

v = 13m/s

Therefore,

K. E = ½mv²

300 = ½ × m × 13²

Multiply both sides by 2

600 = m × 169

Divide both sides by 169

m = 600 ÷ 169

mass = 3.55kg

I hope this was helpful, please mark as brainliest

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nah.   i'm just sleepy.