Algebraicallycalculate the rise time and fall timevalues for a sine wave at an arbitrary frequency f0(expressed in Hz). Assume that the sine wave has zeroaverage, thus Vmin= −Vmax. Express the rise time in units of the period T= 1/ f0.Using your algebraic results, calculate the rise time inμs for the sinusoidal signal at 50 kHz. Keep 4 significantdigits.

185.95 μsec

Explanation:

Given that:

Sine wave =

Sinusodial signal  = 50 kHz =

Rise time is said to be defined as the time needed for a pulse to rise from 10% - 90% of maximum rate.

∴

= 10% = 0.1 Am

=90% = 0.9 Am

Using sine wave for  ; we have:

 = 0.1 Am

= 0.1

= 5.7392

Using sine wave for ; we have:

 = 0.9 Am

=

= 64.158

=

=

Change in rise time = -  

=

=

=

since;    = 50 kHz =

=

= 1.85952 × 10⁻⁴

= 185.952 × 10⁻⁶ sec

=  185.95 μ sec

∴ The rise in time in (μ sec) for the sinosodial signal at 50 kHz = 185.95 μ sec

12000j is work done

v 154.9= 0.9 length length s little over 154.9cm