A preliminary steering inspection reveals that the steering wheel has nearly 1/2 in. of movement in either direction before the pitman arm begins to move. All of the following could cause this problem EXCEPTA. Coupling jointsB. U jointsC. Shafts bearings

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

It is either a  proton or a neutron im almost positive. hope this .