If the potential due to a point charge is 5.15 ✕ 102 V at a distance of 14.8 m, what are the sign and magnitude of the charge? (Enter your answer in C.)

q = 8.47×10⁻⁷ C.

Explanation:

From Coulomb's,

V = kq/r Equation 1

Where, V = Electric potential, q = charge, r = distance, k = proportionality constant.

Make q the subject of the equation

q = Vr/k Equation 2

Given: V = 5.15×10² V, r = 14.8 m

Constant: k = 9.0×10⁹ Nm²/C²

Substitute into equation 2

q = 5.15×10²×14.8/9.0×10⁹

q = 8.47×10⁻⁷ C.

technology is the collection of techniques, skills, methods, and processes used in the the merriam-webster learner's dictionary offers a definition of the term: "the use of moreover, these technologies have become so complex that entire fields more recently, modern works of science fiction such as those by philip k.

explanation:

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.