A Carnot engine operates between reservoirs at 600 and 300 K. If the engine absorbs 100 J per cycle at the hot reservoir, what is its work output per cycle?

50J

For a Carnot engine, the work output (W) per cycle is given by;

W = Q (1 - )          ----------------(i)

Where;

Q = heat absorbed by the engine per cycle

= Temperature of the colder reservoir

= Temperature of the hotter reservoir

From the question;

Q = 100J

= 300K

= 600K

Substitute these values into equation (i) as follows;

W = 100 (1 - )

W = 100 (1 - )

W = 100 ()

W = 50 J

Therefore, the work output per cycle is 50J

no. dot product   =0 when vecs at right angles