A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V. What are (a) the total energy stored in the electric field and (b) the energy density

(A) Total energy will be equal to

(b) Energy density will be equal to

Explanation:

We have given diameter of the plate d = 2 cm = 0.02 m

So area of the plate

Distance between the plates d = 0.50 mm =

Permitivity of free space

Potential difference V =200 volt

Capacitance between the plate is equal to

(a) Total energy stored in the capacitor is equal to

(b) Volume will be equal to , here A is area and d is distance between plates

So energy density

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