You stand 17.5 m from a wall holding a softball. You throw the softball at the wall at an angle of 30.5 ∘ from the ground with an initial speed of 20.5 m / s. At what height above its initial position does the softball hit the wall? Ignore any effects of air resistance.

5.39 m

Explanation:

From kinematics

where t is time, s is distance and is initial speed in x direction

Now 17.5=17.6634 t

=0.99 s

Using the equation of kinematics

h=5.39 m

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