A 12.0 V battery is connected to two resistors in series:
R1 = 12.00 , R2 = 4.00 .

The Req is 16 ohm, total current is same for both i.e. 0.75A  and voltage are 9V and 3V for resistor R1 and R2 respectively.

Explanation:

V(total)= I(total) * Req

or, I(total)=V/Req=12/16=0.75 amp.

Now,

Voltage across R1= I(total) * R1= 0.75* 12=9V

Voltage across R2= I(total) * R2= 0.75* 4=3V

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explanation:

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