In a crash test, a 2000-kg van collides with a concrete support. The stopping time interval for the collision is 0.10 s, and the impulse exerted by the support on the van is 5.5×103 N⋅s.

A. Determine the magnitude of the change in momentum.

B. Determine the magnitude of the average force exerted by the concrete support on the van.

C. If the van is constructed to collapse more during the collision so that the time interval during which the impulse is exerted is tripled, what is the magnitude of the average force exerted by the concrete support on the van?

(a). The magnitude of the change in momentum is

(b). The magnitude of the average force exerted by the concrete support on the van is .

(c). The average force exerted by the concrete support on the van is

Explanation:

Given that,

Mass of van = 2000 kg

Time = 0.10 s

Impulse

(a). We need to calculate the magnitude of the change in momentum

Using impulse-momentum theorem

Change in momentum = impulse

Put the value into the formula

The magnitude of the change in momentum is

(b). We need to calculate the magnitude of the average force exerted by the concrete support on the van.

Using formula of impulse

Put the value into the formula

The magnitude of the average force exerted by the concrete support on the van is .

(c). If the impulse is tripled

As time interval is tripled then average force is reduced one third.

We need to calculate the average force exerted by the concrete support on the van

Using formula of impulse

Put the value into the formula

The average force exerted by the concrete support on the van is

Hence, (a). The magnitude of the change in momentum is

(b). The magnitude of the average force exerted by the concrete support on the van is .

(c). The average force exerted by the concrete support on the van is

d) physical means can be used to separate the components of air.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west