Each plate of a parallel‑plate capacitor is a square of side 4.19 cm, 4.19 cm, and the plates are separated by 0.407 mm. 0.407 mm. The capacitor is charged and stores 7.87 nJ 7.87 nJ of energy. Find the electric field strength inside the capacitor.

The electric field strength inside the capacitor is 49880.77 N/C.

Explanation:

Given:

Side length of the capacitor plate (a) = 4.19 cm = 0.0419 m

Separation between the plates (d) = 0.407 mm =

Energy stored in the capacitor (U) =

Assuming the medium to be air.

So, permittivity of space (ε) =

Area of the square plates is given as:

Capacitance of the capacitor is given as:

Now, we know that, the energy stored in a parallel plate capacitor is given as:

Rewriting in terms of 'E', we get:

Now, plug in the given values and solve for 'E'. This gives,

Therefore, the electric field strength inside the capacitor is 49880.77 N/C

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6