An astronaut on the planet Zircon tosses a rock horizontally with a speed of 7.15 m/s. The rock falls through a vertical distance of 1.40 m and lands a horizontal distance of 8.95 m from the astronaut. What is the size of the acceleration due to gravity on Zircon

Explanation:

horizontal velocity, u = 71.5 m/s

height, h = 1.4 m

horizontal distance, d = 8.95 m

Let the time is t and the value of acceleration at that planet is a.

Use second equation of motion

d = u t ( acceleration in horizontal direction is zero)

8.95 = 71.5 x t

t = 0.125 s

Use second equation of motion in vertical direction

h = 1/2 at²

1.4 = 1/2 x a x 0.125 x 0.125

a = 17.2 m/s²

3.2x10^7

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