Physics, 21.02.2020 17:44, meechristianp

A Lambda particle Λ decays into a proton p and a pion π, Λ → p + π, and it is observed that the proton is left at rest. (a) What is the energy of the pion? (b) What was the energy of the Lambda particle? Derive your results analytically and then calculate the answers using mΛ = 1116 MeV, mp = 938 MeV, mπ = 140 MeV (masses are expressed in units c = 1).

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A Lambda particle Λ decays into a proton p and a pion π, Λ → p + π, and it is observed that the prot...