What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of – 30.0 nC?

Explanation:

Assuming the pith balls as point charges, we can calculate the repulsive force between them, using Coulomb's law:

We observe that the magnitude of the electric force is directly proportional to the product of the magnitude of both signed charges() and inversely proportional to the square of the distance(d) that separates them.

Replacing the given values, where k is the Coulomb constant:

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explanation:

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