Four point charges of magnitudes 3q q 2q and 4q are arranged in the corners of a square of side length L. The charge q creates a potential of 1 V relative to infinity in the center of the square.

What is the total potential created in the center of a square by all 4 charges?

a. 1V
b. 10V
c. It is impossible to determine without knowing the exact arrangement.
d. 0V
e. 5V

d. 0V

Explanation:

The magnitude of four point charges are +3q, -q, +2q and -4q. I think you forget to mention the signs.

As we know that the potential due to the point charge that has traveled the distance d can be represented mathematically as,

= 1/4λε = 9× Nm²/C²

Now as it is mentioned in the question that all four charges are arranged in the corners of a square so there distance from the center is same. We can rewrite the above potential equation as follows.

       (1)

We can find out d by the pythagoras theorem, as we are dealing with square so d is a semi diagonal.

by putting all values in equation (1)

V =

V = 0V

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.