Calculate the impulse (in kgm/s) received by a football when it's kicked in a kickoff. The ball has a mass of 0.27 kg and travels a horizontal distance of 68 m. The ball is kicked at an angle q of 20.5 with the horizontal and spends 2.276 seconds in the air.

Impulse experienced by the ball = 8.61 kgm/s

Explanation:

Impulse is given as change in momentum according to Newton's second law of motion

Impulse = mv (assuming the ball goes to rest after being kicked)

Range of a projectile is given as

R = uₓt

uₓ = horizontal component of the velocity = u cos(θ) = u cos 20.5° = 0.9367 u

t = time of flight, given in the question as 2.276 s

R = 68 m

68 = 0.9367 u × 2.276 = 2.132 u

u = 31.9 m/s

Impulse = mv = 0.27 × 31.9 = 8.61 kgm/s

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle